Question

4 points

221.7 g sample of water that begins at 25.0 degrees Celsius is heated with 3560.6 calories of heat. What is the final temperature of the w
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Answer 1

The final temperature of the water is 41.05 degrees celsius.

Step-by-step explanation:

We have,

Mass of sample of water is 221.7 g

Initial temperature was 25.0 degrees Celsius

Heat produced in it is 3560.6 calories of heat

The specific heat capacity of water is 4.186 J/g °C

1 calorie = 4.184 J

3560.6 calorie = 14897.55 J

The heat produced due to change in temperature is given by :

`Q=mc(T_f-T_i)`

c is specific heat capacity

`T_f=(Q)/(mc)+T_i\\\\T_f=(14897.55)/(221.7* 4.186)+25\\\\T_f=41.05\ ^(\circ)C`

So, the final temperature of the water is 41.05 degrees celsius.