217k views
2 votes
What is the completely factored form of 3x^5-7x^4+6x^2-14x?

User Tonino
by
6.8k points

1 Answer

4 votes

Answer:

x(x - 7)(x^3 + 2)

Explanation:

Note that x is a common factor here:

3x^5-7x^4+6x^2-14x = x(3x^4 - 7x^3 + 6x - 14), or:

x(3x^4 - 7x^3 + 6x - 14) Note that 6x - 14 can be rewritten as 2[x - 7]

and that 3x^4 - 7x^3 can be rewritten as x^3[x - 7]

Therefore, x(3x^4 - 7x^3 + 6x - 14 becomes:

x(x - 7)(x^3 + 2)

User Debbieann
by
7.2k points