Answer:
And for this case we can begin completing the square like this:
![f(x) = x^2 +10x + (10/2)^2 +21 -(10/2)^2](https://img.qammunity.org/2021/formulas/mathematics/college/ul1xrxgxg8r1lt6qv5sxy9irtkamafbfd7.png)
And after aggrupate the terms we got:
![f(x) = (x+5)^2 +21 -25](https://img.qammunity.org/2021/formulas/mathematics/college/lvlas3wjgcyi2jif97illx1tcgye3tjsje.png)
And finally we have:
![f(X)= (x+5)^2 -4](https://img.qammunity.org/2021/formulas/mathematics/college/nusjnbgld5o14k8pd1ur2gsefnodtlvnyk.png)
And for this case our vertex would be:
![(h,k) = (-5,-4)](https://img.qammunity.org/2021/formulas/mathematics/college/mzicja32choizw1ojmzxc38kbucwouwd9y.png)
Explanation:
For this case we have the following equation given:
![f(x) = x^2 +10x +21](https://img.qammunity.org/2021/formulas/mathematics/college/f9xma3llvgvb0rro6haoozg0u020a6arga.png)
And we want to find a formula in terms in the vertex form given by:
![f(x) = a(x-h)^2 +k](https://img.qammunity.org/2021/formulas/mathematics/college/ec4jad1t9hcbayxxe144q4ne20bn0lvf0s.png)
And for this case we can begin completing the square like this:
![f(x) = x^2 +10x + (10/2)^2 +21 -(10/2)^2](https://img.qammunity.org/2021/formulas/mathematics/college/ul1xrxgxg8r1lt6qv5sxy9irtkamafbfd7.png)
And after aggrupate the terms we got:
![f(x) = (x+5)^2 +21 -25](https://img.qammunity.org/2021/formulas/mathematics/college/lvlas3wjgcyi2jif97illx1tcgye3tjsje.png)
And finally we have:
![f(X)= (x+5)^2 -4](https://img.qammunity.org/2021/formulas/mathematics/college/nusjnbgld5o14k8pd1ur2gsefnodtlvnyk.png)
And for this case our vertex would be:
![(h,k) = (-5,-4)](https://img.qammunity.org/2021/formulas/mathematics/college/mzicja32choizw1ojmzxc38kbucwouwd9y.png)