Question

Could someone help me super fast? no fake answers please

optionally could someone help me too with any of the other questions on my profile they are worth 50 points each too

Answer 1

Vertex form of parabola having vertex (h,k)

• y=a(x-h)²+k

#1

• y=a(x-2)²+3

Vertex (2,3)

• Graph III

#2

• y=(x+2)²-3

Vertex (-2,-3)

• Graph V

#3

• y=(x+3)²-2

Vertex (-3,-2)

• Graph II

#4

• y=(x-3)²+2

Vertex (3,2)

• Graph IV

Answer 2

(a) graph iii)

(b) graph v)

(c) graph ii)

(d) graph iv)

Explanation:

All given equations are in vertex form: y = (x - h)² + k

where (h, k) is the vertex of the parabola

The vertex is the turning point of the parabola, so the minimum point for parabolas that open upward, and the maximum point for parabolas that open downward.

Vertices of the given graphs:

i) (-3, 2)

ii) (-3, -2)

iii) (2, 3)

iv) (3, 2)

v) (-2, -3)

vi) (2, -3)

Part (a)

Given equation: y = (x - 2)² + 3

Therefore, the vertex is (2, 3) → graph iii)

Part (b)

Given equation: y = (x + 2)² - 3

Therefore, the vertex is (-2, -3) → graph v)

Part (c)

Given equation: y = (x + 3)² - 2

Therefore, the vertex is (-3, -2) → graph ii)

Part (d)

Given equation: y = (x - 3)² + 2

Therefore, the vertex is (3, 2) → graph iv)