Question

Find the equation of the perpendicular bisector of line MN

Answer 1

Y=(-1/2)x+9/2

Explanation:

For straight lines y=mx+c

m=gradient

Find the gradient first-m=(y2-y1) /(x2-x1)

Take the points M and N and substitute in the equation

m=(5-2)/(-1-5)

m=-1/2

Gradient of line MN×gradient of perp line =-1

There fore gradient of perp line =2