Answer:
![y=5 \ \ \ x<x_o\\\\y=0.47x\ \ \ x_o < x < x_o+1.9\\\\y=5.9\ \ \ x > x_o + 1.9s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wea61u15vcgxz7tl4mxxw6px5r4wa2cmtw.png)
Explanation:
This situation can be considered as a piecewise function. First, you take xo as the time in which the drone goes upward. Before this time the height of the drone is constant with a value of 5 m. Next, you take into account that during 1.9 s after xo the drone accelerates. Finally, the drone flies again with a constant height of 5.9m. Hence, this function has three parts:
For the first part you have:
y = 5 for x < xo
For the second part you first calculate vertical speed (which means the slope of the linear function) by using the following kinematic equation:
![y=vx\\\\v=(y-y_o)/(x)=(5.9m-5.0m)/(1.9s)=0.47m/s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/15szjprojkrlf4s8bdqgxqjmwk5h7h6h4a.png)
Then you have:
y = 0.47x for xo < x < xo + 1.9s
And for the third part:
y = 5.9 for x > xo + 1.9s
Summarizing you obtain:
![y=5 \ \ \ x<x_o\\\\y=0.47x\ \ \ x_o < x < x_o+1.9\\\\y=5.9\ \ \ x > x_o + 1.9s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wea61u15vcgxz7tl4mxxw6px5r4wa2cmtw.png)