Question

A skier is going down a hill at an initial velocity of 9 m/s East. The hill gets steeper and the skier's velocity increases to 18 m/s

East in 3 seconds. Find the acceleration.

MEANING

Answer 1

The acceleration of the skier is 3 m/s² eastward, calculated by dividing the change in velocity (9 m/s) by the time interval (3 s).

Step-by-step explanation:

The question involves finding the acceleration of a skier who increases their velocity from 9 m/s to 18 m/s eastward over a time interval of 3 seconds. To find acceleration, we use the formula a = ∆v / ∆t, where ∆v is the change in velocity, and ∆t is the change in time. The change in velocity (∆v) is 18 m/s - 9 m/s = 9 m/s. The change in time (∆t) is 3 seconds. Therefore, the acceleration (a) is 9 m/s ÷ 3 s = 3 m/s² eastward.

The skier's acceleration can be calculated using the equation:

a = (vf - vi) / t

where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.

In this case, the initial velocity is 9 m/s East, the final velocity is 18 m/s East, and the time interval is 3 seconds.

Plugging in these values, we get:

a = (18 m/s - 9 m/s) / 3 s = 3 m/s² East

Therefore, the acceleration of the skier is 3 m/s² East.

Answer 2

Acceleration is 3m/s2

Step-by-step explanation:

From the question, the formula for acceleration is ∆velocit÷∆time.

V1=9m/s

V2=18m/s

T1=0 seconds

T2=3 seconds.

V1 represent initial velocity

V2 represent final velocity

T1 represent initial time

T2 represent final time.

Acceleration=v2-v1÷T2-T1

=18-9/3-0

=9÷3

=3m/s2.

Acceleration is 3m/s2.

Acceleration is the rate of change of velocity of a body per unit time.