219k views
0 votes
A skier is going down a hill at an initial velocity of 9 m/s East. The hill gets steeper and the skier's velocity increases to 18 m/s

East in 3 seconds. Find the acceleration.

MEANING

User Ohiodoug
by
9.1k points

2 Answers

6 votes

Final answer:

The acceleration of the skier is 3 m/s² eastward, calculated by dividing the change in velocity (9 m/s) by the time interval (3 s).

Step-by-step explanation:

The question involves finding the acceleration of a skier who increases their velocity from 9 m/s to 18 m/s eastward over a time interval of 3 seconds. To find acceleration, we use the formula a = ∆v / ∆t, where ∆v is the change in velocity, and ∆t is the change in time. The change in velocity (∆v) is 18 m/s - 9 m/s = 9 m/s. The change in time (∆t) is 3 seconds. Therefore, the acceleration (a) is 9 m/s ÷ 3 s = 3 m/s² eastward.

The skier's acceleration can be calculated using the equation:

a = (vf - vi) / t

where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.

In this case, the initial velocity is 9 m/s East, the final velocity is 18 m/s East, and the time interval is 3 seconds.

Plugging in these values, we get:

a = (18 m/s - 9 m/s) / 3 s = 3 m/s² East

Therefore, the acceleration of the skier is 3 m/s² East.

User William Briand
by
8.4k points
4 votes

Answer:

Acceleration is 3m/s2

Step-by-step explanation:

From the question, the formula for acceleration is ∆velocit÷∆time.

V1=9m/s

V2=18m/s

T1=0 seconds

T2=3 seconds.

V1 represent initial velocity

V2 represent final velocity

T1 represent initial time

T2 represent final time.

Acceleration=v2-v1÷T2-T1

=18-9/3-0

=9÷3

=3m/s2.

Acceleration is 3m/s2.

Acceleration is the rate of change of velocity of a body per unit time.

User Chris Klingler
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories