Question

Determine the equation of the line perpendicular to the line y = –8 through the point (–4, –2).

The line y = –8 is .

The line perpendicular to the line y = –8 is .

The equation of the line perpendicular to the line y = –8 through the point (–4, –2) is .

Answer 1

Determine the equation of the line perpendicular to the line y = –8 through the point (–4, –2).The line y = –8 is ✔ horizontalslantedvertical.The line perpendicular to the line y = –8 is horizontalslanted✔ vertical.The equation of the line perpendicular to the line y = –8 through the point (–4, –2) is ✔ x = –4y = –4x = –2y = –2.

Explanation:

Determine the equation of the line perpendicular to the line y = –8 through the point (–4, –2).The line y = –8 is ✔ horizontalslantedvertical.The line perpendicular to the line y = –8 is horizontalslanted✔ vertical.The equation of the line perpendicular to the line y = –8 through the point (–4, –2) is ✔ x = –4y = –4x = –2y = –2.

Answer 2

x = - 4

Explanation:

y = - 8 is the equation of a horizontal line parallel to the x- axis.

A perpendicular line must then be a vertical line parallel to the y- axis.

The equation of a vertical line is x = c

where c is the value of the x- coordinates it passes through.

The line passes through (- 4, - 2) with x- coordinate - 4, thus

x = - 4 ← equation of perpendicular line