232k views
16 votes
(2,-1);5x-7y=8 write an equation of a line containing the given point and parallel to the given line

2 Answers

13 votes
  • 5x-7y=8

Isolate y

  • 7y=5x-8
  • y=5/7x-8/7

Here

  • m=5/7

Parallel lines have equal slope

Point(2,-1)

Equation of line in point slope form


\\ \sf\longmapsto y-y_1=m(x-x_1)


\\ \sf\longmapsto y+1=5/7(x-2)


\\ \sf\longmapsto 7y+7=5x-10


\\ \sf\longmapsto 5x-7y-17=0

User Jazmin
by
8.1k points
9 votes

Answer:

  • 5x - 7y = 17

Explanation:

Given line:

  • 5x - 7y = 8

Convert the equation into slope-intercept form:

  • 5x - 7y = 8
  • 7y = 5x - 8
  • y = 5/7x - 8/7

The line parallel to this has same slope of 5/7 and passes through the point (2, - 1).

Use point-slope form and convert the equation into standard form:

  • y - (- 1) = 5/7(x - 2)
  • y + 1 = 5/7x - 10/7
  • 7y + 7 = 5x - 10
  • 5x - 7y = 7 + 10
  • 5x - 7y = 17
User Sherwayne
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories