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The clock period of a ripple counter must be longer than the total propagation

delays through all of the flip-flops. For proper operation, the period / frequency
should be:
Tmin = N x tpd where tpd is the propagation delay fmax = 1/ Tmin = 1/ (N x tpd).
If the propagation delay is 15ns for a J-K FF, what is the largest
MOD counter that can be constructed to ensure the counter will operate for
frequencies > 12 MHz?

User Almog Baku
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1 Answer

5 votes

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem

The clock period of a ripple counter must be longer than the total propagation delays-example-1
User Jaysonpryde
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