Question

Suppose a medium pizza at Vincent's costs $6.75 plus $0.75 for each topping, and the cost of a medium pizza at Original Italian Pizza is $6.15 plus $0.80 per topping. How many toppings would you have to include on your pizza for the price to be the same at both places?

Answer 1

12 toppings and the prize will be the same.

Explanation:

Let

number of toppings = a

Medium pizza at Vincent's

cost = 6.75 + 0.75a

Medium pizza at Original Italian Pizza

cost = 6.15 + 0.80a

For the cost to be the same

6.75 + 0.75a = 6.15 + 0.80a

collect like terms

6.75 - 6.15 = 0.80a - 0.75a

0.6 = 0.05a

divide both sides by 0.05

a = 0.6/0.05

a = 12

12 toppings and the prize will be the same.

Answer 2

12 toppings

Explanation:

To do this, we need to write an equation for each place, and then, equal both equations to solve for this.

Let's call "y" the price of the pizza, and "x" the number of toppings.

At Vincents, pizza costs 6.75 + 0.75 for each topping, so the equation here would be:

y = 6.75 + 0.75x (1)

Now, at italian pizza, a pizza costs 6.15 + 0.80 per topping, so the equation:

y = 6.15 + 0.80x (2)

Now, we don't need to know the actual price of the pizza, we only want to know how many toppings we need to add on both places, so the pizza has the same price. We have both equations, it's time to equal both of them:

Equalling (1) and (2) we have:

6.75 + 0.75x = 6.15 + 0.80x

Now, let's solve for x:

6.75 - 6.15 = 0.80x - 0.75x

0.6 = 0.05x

x = 0.6 / 0.05

x = 12

So the number of toppings to include in the pizza so the price is the same for both places, will have to be 12 toppings.