Question

What is the slope of the line passing through (13,-2) and (3,-2)

Answer 1

Slope (m) =0

Slope (m) =

ΔY

ΔX

= 0

θ =

arctan( ΔY )

ΔX

= 0°

ΔX = 3 – 13 = -10

ΔY = -2 – -2 = 0

Distance (d) = √ΔX2 + ΔY2 = √100 = 10