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2 votes
How many mL of solution of 2. 00 M KI would you need to

prepare 100 mL of a 0. 600 M KI solution?

User Amitesh
by
5.0k points

1 Answer

12 votes
Answer:

30 mL

Step-by-step explanation:

Molarity1 x Volume1 = Molarity2 x Volume2

So, we need V2.
We rearrange the equation like a normal algebra equation.

(0.6 x 100)/2 = V2

V2 = 30
User Avi Das
by
5.3k points