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Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m? •m²+3m+2=0 •m²-3m+17=0 •m²-3m+2=0 •m²+3m+17=0​

Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m? •m²+3m+2=0 •m²-3m+17=0 •m²-3m+2=0 •m²+3m+17=0​
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Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m?

•m²+3m+2=0
•m²-3m+17=0
•m²-3m+2=0
•m²+3m+17=0​

User Century Tuna
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1 Answer

5 votes

Explanation:

#1

User Nick Fury
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