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Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m? •m²+3m+2=0 •m²-3m+17=0 •m²-3m+2=0 •m²+3m+17=0
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Oct 5, 2021
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Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m?
•m²+3m+2=0
•m²-3m+17=0
•m²-3m+2=0
•m²+3m+17=0
Mathematics
middle-school
Century Tuna
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Nick Fury
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