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Identify the graph of the equation... Then find q to the nearest degree. 16x^2+2xy+y^2-16=0

Identify the graph of the equation... Then find q to the nearest degree. 16x^2+2xy+y^2-16=0
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5 votes
Identify the graph of the equation... Then find q to the nearest degree.

16x^2+2xy+y^2-16=0

User KNOWARTH
by
8.4k points

2 Answers

5 votes
We need a picture of the graph first
User Mdargacz
by
8.0k points
2 votes

Answer:

ellipse ; 4 degrees

Explanation:

edge’s possible answer 2020

User Todd Gardner
by
8.5k points
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