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Solve equations using structure

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Let m = x2 + 3.
Which equation is equivalent to (x2 + 3)2 + 7x2 + 21 =
10 in terms of m?

1 Answer

5 votes

Answer:
9m=10 or
m=(10)/(9)

I don't know your options... but you can check my work below and see if any of the other options fit yours.

Explanation:


(x^2 + 3)2 + 7x^2 + 21 =10

If
x^2+3=m, we can rewrite this as;


(m)2+7x^2+21=10\\2m+7x^2+21=10

By grouping, we can factor another m.


2m+(7x^2+21)=10

Factor a 7.


2m+7(x^2+3)=10

Rewrite it in terms of m.


2m+7m=10

Combine like terms;


9m=10

Divide by 9


m=(10)/(9)

User Remul
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