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A student is ordering a flower arrangement. She can choose any combination of tulip and carnations for her flower arrangement , and she does not want to spend more than $45. If tulip cost $5 each and carnations cost $3 each, which inequality represents all possible combinations of x tulips and y carnations ? A. 5x + 3y < 45 B. 5x + 3y <= 45 C. 3x + 5y > 45 3x + 5y <= 45

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2 Answers

6 votes

Answer:

it would be 5x + 3y <= 45

Explanation:

I literally just did this question on my math homework and I got it right .

User Naresh Kumar P
by
3.1k points
3 votes

Answer:


5x+3x \leq 45 represents all possible combinations of x tulips and y carnations

Explanation:

We are supposed to find inequality represents all possible combinations of x tulips and y carnations

Cost of 1 tulip = $5

Cost of x tulips = 5x

Cost of 1 carnation =$3

Cost of y carnations = 3y

We are given that she does not want to spend more than $45.

So, She can spend less than or equal to 45

So, required inequality :
5x+3x \leq 45

So, Option B is true


5x+3x \leq 45 represents all possible combinations of x tulips and y carnations

User Mbrannig
by
3.0k points