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PLEASE HELP!!!!!! DUE!!!!!!!!!

Write the slope-intercept form of an equation for the line that passes through the given point and is perpendicular to the graph of the given equation.
(−4,−3) and 8x+2y=14

User Rafalry
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3.2k points

1 Answer

1 vote

Answer:

y = 1/4x - 2

Explanation:

Line whose perpendicular which we have to find : 8x+2y=14

A line which is in the form of ax + by = c

has slope - a / b

Thus slope for 8x+2y=14 is -8/2 = -4.

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Slope of two lines with slope m1 and m2 which are perpendicular to each other have the slope relation as

m1*m2 = -1.

here m1 is -4. we have to fine m2

thus

-4*m2 = -1

=> m2 = -1/-4 = 1/4

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Equation of slope intercept form line is y = mx + c

c is the intercept of line on y axis

and m is the slope of line.

Thus required line has equation

y = mx + c

m we have calculated as 1/4

thus

y = 1/4x + c

Given that this line passes through (−4,−3). Hence, this point will satify the equation y = 1/4x + c.

Substituting value of x and y with coordinates we have (−4,−3)

-3 = (1/4) * (-4) + c

-3 = -1 + c

=> c = -3 + 1

=> c = -2

y = 1/4x + c , substituting the value c calculated

y = 1/4x - 2

Thus , equation of line perpendicular to the line 8x+2y=14 and passing through point (−4,−3) is y = 1/4x - 2.

User Dmitry Mina
by
3.7k points