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In the diagram below, point P is circumscribed about quadrilateral ABCD. What is the value of x? (Pls answer I give lot of point)

In the diagram below, point P is circumscribed about quadrilateral ABCD. What is the-example-1

2 Answers

3 votes

Answer:

D. 50

Explanation:

130+x=180

x=50

User Mihagazvoda
by
7.3k points
2 votes

The value of
\( x \) is 50 degrees, which corresponds to option D.

The diagram shows a circle circumscribed around quadrilateral ABCD, with an angle at C that is 130 degrees. Assuming that ABCD is a cyclic quadrilateral (a quadrilateral whose vertices all lie on the circumference of a circle), then the opposite angles of a cyclic quadrilateral sum up to 180 degrees due to the Inscribed Angle Theorem. This theorem states that the opposite angles of a cyclic quadrilateral are supplementary.

Given that angle
\( \angle C \) is 130 degrees, we can find the measure of angle
\( \angle A \) by the following relationship for a cyclic quadrilateral:


\[ \angle A + \angle C = 180^\circ \]

Plugging in the value for
\( \angle C \), we get:


\[ \angle A + 130^\circ = 180^\circ \]

Now, let's calculate the value of angle
\( \angle A \):


\[ \angle A = 180^\circ - 130^\circ \]


\[ \angle A = 50^\circ \]

Therefore, The answer is 50 degrees.

User Dzmitry Vasilevsky
by
7.6k points

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