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I NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!

I NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!-example-1
User Lahar Shah
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1 Answer

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Answer:

1. x² - 16x = -12

2. x² - 16x + 64 = -12 + 64

3. (x - 8)² = 52

4. x - 8 = ± √52

5. x = 8 ± √52

6. x = 8 ± 2√13

Explanation:

1. Move the constant to the other side of the equation:

x² - 16x +12-12 = 0-12

x² - 16x = -12

2. Find the new value of c by using the formula
((b)/(2) )^(2)


((-16)/(2) )^(2)\\\\(-8)^(2) \\\\c =64

3. Plug the new value of c into the equation. Make sure to add it to both sides of the equation, because if you do something to one side, you must do it to the other:

x² - 16x + 64 = -12 + 64

x² - 16x + 64 = 52

4. Form a perfect sqaure by factoring -16 and 64 by figuring out two numbers that have a sum of -16 and a product of 64:

-8 + (-8) = -16
-8 · (-8) = 64

(x - 8)²

Plugging this into the equation:

(x - 8)² = 52

5. Take the square root of both sides:

√(x - 8)² = √52

x - 8 = √52

6. Isolate x:

x - 8+8 = 2√52+8

x = 8 ± 2√52

52 can be squared, so:

x = 8 ± 2√13

hope this helps!

User Slava Rozhnev
by
8.1k points

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