Final answer:
The balanced equation for the reaction between glucose and oxygen is C6H12O6 + 6O2 → 6CO2 + 6H2O. To calculate the mass of oxygen required for the complete reaction of 25.0 g of glucose, we can use the molar masses and the mole ratios from the balanced equation. We find that 4.39 g of oxygen is required. We can also calculate the masses of carbon dioxide and water formed, which are 7.36 g and 2.98 g, respectively.
Step-by-step explanation:
The balanced equation for the reaction between glucose (C6H12O6) and oxygen (O2) to produce carbon dioxide (CO2) and water (H2O) is:
C6H12O6 + 6O2 → 6CO2 + 6H2O
To calculate the mass of oxygen required for the complete reaction of 25.0 g of glucose, we need to use the molar masses of glucose and oxygen. From the given information, the molar mass of glucose is 180.16 g/mol and the molar mass of oxygen is 31.9988 g/mol. The ratio between glucose and oxygen in the balanced equation is 1:6. Therefore, we can set up the following proportion:
(25.0 g glucose) / (180.16 g/mol) = (x g oxygen) / (31.9988 g/mol)
Solving for x, we find that x = 4.39 g of oxygen is required for the complete reaction of 25.0 g of glucose.
To calculate the masses of carbon dioxide and water formed, we can use the same approach. Based on the balanced equation, the ratio between glucose and carbon dioxide is 1:6 and the ratio between glucose and water is 1:6. Therefore, we can set up the following proportions:
(25.0 g glucose) / (180.16 g/mol) = (x g carbon dioxide) / (44.010 g/mol)
(25.0 g glucose) / (180.16 g/mol) = (x g water) / (18.015 g/mol)
Solving for x in each proportion, we find that x = 7.36 g of carbon dioxide and x = 2.98 g of water are formed.