Question

If 8 moles of FeCl react with 8 moles of O2 what is the limiting reactant?

4FeCl3 + 302—2Fe2O3 + 3Cl2

A) FeCl3
B) 02
C) Fe203
D) Cl2

Answer 1

A) FeCl₃

Step-by-step explanation:

Hope this helps

Answer 2

A) FeCl₃

Step-by-step explanation:

The only unclear part here is what the product is meant to be. But, I will put in the limiting reactant for both cases.

4 FeCl₃ + 3 O₂ ⇒ 2 Fe₂O₃ + 3 Cl₂

For Fe₂O₃:

Use the stoichiometry from the chemical equation to solve this problem.

You need 4 moles of FeCl₃ to make 2 moles of Fe₂O₃.

8 × (2/4) = 4 moles

You need 3 moles of O₂ to make 2 moles of Fe₂O₃.

8 × (2/3) = 5.3 moles

Since FeCl₃ made less product, it is the limiting reactant.

For Cl₂:

Do the same as above.

You need 4 moles of FeCl₃ to make 3 moles of Cl₂.

8 × (3/4) = 6 moles

You need 3 moles of O₂ to make 3 moles of Cl₂.

8 × (3/3) = 8 moles

Since FeCl₃ made less product, it is the limiting reactant.