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How many atoms are in 0.075 mol of helium

1 Answer

6 votes

Answer:

4.52 ×10²² atoms (3 s.f.)

Step-by-step explanation:

Number of atoms

= number of moles × Avogadro's constant

= number of moles × 6.022 ×10²³

Number of atoms

= 0.075 × 6.022 ×10²³

= 4.52 ×10²² (3 s.f.)

User Adrian Lambertz
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