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A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of the change in momentum of the rock?

2 Answers

6 votes

Answer:

8.7

Step-by-step explanation:

User Drew McGowen
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3 votes

Answer:

The change in momentum is
\Delta p = 0.7 \ kg\cdot m \cdot s^(-1)

Step-by-step explanation:

From the question we are told that

The time taken for the stone to stop is
\Delta t = 0.15 \ seconds

The net force on the rock is
F = 58 \ N

The impulse of the rock can be mathematically represented as


I = F * \Delta t

Substituting values


I = 58 * 0.15


I = 0.7\ kg * m * s^(-1)

Now impulse is defined as the rate at which momentum change

Hence the change in momentum
\Delta p of the rock is equal to the impulse of the rock

So


\Delta p = I = 0.7 \ kg\cdot m \cdot s^(-1)

User Antonin Stefanutti
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3.2k points