Question

A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of the change in momentum of the rock?

Answer 1

8.7

Step-by-step explanation:

Answer 2

The change in momentum is
`\Delta p = 0.7 \ kg\cdot m \cdot s^(-1)`

Step-by-step explanation:

From the question we are told that

The time taken for the stone to stop is
`\Delta t = 0.15 \ seconds`

The net force on the rock is
`F = 58 \ N`

The impulse of the rock can be mathematically represented as

`I = F * \Delta t`

Substituting values

`I = 58 * 0.15`

`I = 0.7\ kg * m * s^(-1)`

Now impulse is defined as the rate at which momentum change

Hence the change in momentum
`\Delta p` of the rock is equal to the impulse of the rock

So

`\Delta p = I = 0.7 \ kg\cdot m \cdot s^(-1)`