Question

In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percent yield of this reaction? *

85.0%
72.0%
75.0%
67.0%

Answer 1

75.0%

Step-by-step explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%