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The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired target, a phenomenon referred to as off-target cleavage. To avoid off-target cleavage, sites targeted for mutation should appear only once in the genome. What is the minimum length of the part of an sgRNA molecule that binds DNA whose base pair sequence would be expected to be unique within the fruit fly genome

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Answer:

correct answer: 14

Step-by-step explanation:

the question is incomplete, so a graph with the complete questionnaire is attached and the requested question is answered

We will start from the exercise requesting the minimum length that a sequence forms with more than 1.4x10ˆ8 permutations

for this we deduce that two base pairs can have:

4 * 4 = 16 permutations

we deduce that 3 base pairs can have:

4 * 4 * 4 = 64 permutations

Thus we multiply successively until we reach that 14 base pairs can obtain: 2.68x10ˆ8 permutations that are random

Thus, the 14bp sequence will be found only once in the genome of the fruit fly.

The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired-example-1
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