Question

Please help and explain

Answer 1

Answer: A,B

Explanation:

`((3^2*3^-^2)/(3^3))^2`

You can distribute the exponent.

`(3^2^*^2*3^-^2^*^2)/(3^3^*^2) =(3^4*3^-^4)/(3^6)`

or you can simplify first and then square.

`((3^2*3^-^2)/(3^3))^2`

`((3^2^+^(^-^2^))/(3^3))^2`

`((3^0)/(3^3))^2=((1)/(3^3) )^2=((1)^2)/((3^3)^2)=(1)/(3^6)`

Answer 2

A and B.

Explanation:

If we simplified this equation, we could begin by dealing with the exponents inside of the parenthesis. Remember, when multiplying you will need to add exponents.

This gives us:

`((3^(2)*3^(-2) )/(3^(3)) )^(2)` -->
`((3^(0))/(3^(3)) )^(2)`

Simplifying this gets us:

`((1)/(3^(3)) )^(2)`

Now, multiply the exponent outside of the parenthesis with the exponent inside resulting in:

`(1)/(3^(6))`

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Reasoning for answer A:

The step of multiplying the outside exponents with those inside was done first:

`((3^(2)*3^(-2) )/(3^(3)) )^(2)` -->
`(3^(4)*3^(-4) )/(3^(6))`

Therefore, we get answers A and B.