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What is the equation to the quadratic function that has zeros at -6 and 16?

Group of answer choices

x2 + 22x + 96 = 0

x2 + 10x - 96 = 0

x2 - 22x + 96 = 0

x2 - 10x - 96 = 0

User Budgie
by
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1 Answer

3 votes

Answer:

x^2 -10x -96 =0

Explanation:

Subtract the zeros from x in factors

(x - -6) (x-16)

(x+6) (x-16)

Set these equal to zero since they are zeros

(x+6) (x-16) =0

FOIL

x^2 -16x+6x -96 =0

x^2 -10x -96 =0

User Shakeera
by
8.6k points

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