Question

What is the volume of solution (in mL) produced when 91.80g of Mg(OH)2 are used

to produce a 0.7M solution? Record your answer to 1 decimal places.

Answer 1

Answer: The volume of solution is 2248 ml

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

moles of
`Mg(OH)_2` =
`\frac{\text {given mass}}{\text {Molar mass}}=(91.80g)/(58.32g/mol)=1.574mol`

Now put all the given values in the formula of molality, we get

`0.7=(1.574* 1000)/(V_s)`

`V_s=(1.574* 1000)/(0.7)=2248ml`

Therefore, the volume of solution is 2248 ml