Good evening
Answer:
(0 , 5) and (0 , 11)
Explanation:
Suppose M(x , y) is a point of the circle of center (6,3) and radius 10 and M is also a point of the y-axis then the coordonates of M should verify these two equations at the same time:
![\left \{ {(x-6)^(2) +(y-3)^2=10^(2) } \atop {x=0}} \right.](https://img.qammunity.org/2021/formulas/mathematics/high-school/ak0m125328czwdlbofjugnzt900hjnmn8k.png)
Then
(0-6)² + (y-3)² = 100
then
36 + (y-3)² = 100
then
(y-3)² = 100 - 36
= 64
then
|y-3| = 8
then
y - 3 = 8 or y - 3 = -8
then
y = 11 or y = 5
then the only points that are on the edge of the circle and on y-axis are:
(0 , 5) and (0 , 11).
:)