315 views
2 votes
Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6,3). Which point on the y-axis could be on the edge of the circle of the distance from the center of the circle to the edge is 10

User Bea
by
8.7k points

2 Answers

4 votes

Answer:

(0, –5)

Explanation:

If you don't see this option there is another option, (0 , 11) is also correct

User Kregus
by
9.3k points
3 votes

Good evening

Answer:

(0 , 5) and (0 , 11)

Explanation:

Suppose M(x , y) is a point of the circle of center (6,3) and radius 10 and M is also a point of the y-axis then the coordonates of M should verify these two equations at the same time:


\left \{ {(x-6)^(2) +(y-3)^2=10^(2) } \atop {x=0}} \right.

Then

(0-6)² + (y-3)² = 100

then

36 + (y-3)² = 100

then

(y-3)² = 100 - 36

= 64

then

|y-3| = 8

then

y - 3 = 8 or y - 3 = -8

then

y = 11 or y = 5

then the only points that are on the edge of the circle and on y-axis are:

(0 , 5) and (0 , 11).

:)

User Nknight
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories