Question

Determine the temperature of 2.49 moles of gas in a 1.0-L vessel at 143

kPa. R=8.31 kPa*L/(mol*K) Round your answer to 2 sig figs. *​

Answer 1

Temperature = 6.91K

Step-by-step explanation:

Temperature = T

Number of Moles = 2.49moles

Volume = 1.0L

Pressure = 143kPa

R = 8.31kPa*L/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume which the gas occupies

n = number of moles of the gas

R = ideal gas constant

T = temperature of the ideal gas

PV = nRT

T = PV / nR

T = (143 * 1) / (2.49 * 8.31)

T = 143 / 20.6919

T = 6.91K

The temperature of the gas is 6.91K