190k views
13 votes
The length of a rectangle is 8 feet more than its width. the area of the rectangle is 97 ft.² determine the length and width of the rectangle

User Seapy
by
8.0k points

1 Answer

14 votes

Answer:

L =
√(113) +4

W =
√(113) -4

or L = 14.63 ft, and W = 6.63 ft

Explanation:

Let L be the length and W the width.

We are told that the "length of a rectangle is 8 feet more than its width:"

L = W+8

Area of the rectangle is given by L*W, and is 97
ft^(2)

L*W = 97

Substituting L=W+8, we get:

(W+8)W=97
ft^(2)


W^(2) + 8W = 97


W^(2) + 8W - 97 = 0

The roots to this equation are:

  • -4-
    √(113), and

  • √(113) -4

Only the second gives a positive value, so W =
√(113) -4

Since L=W+8, the length, L, is
√(113) -4 + 8 or
√(113) +4

In decimal:

L = 14.63 ft, and W = 6.63 ft

User Mlapaglia
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories