2 Answers

Zallarak · Answer 1 · 2021-11-14T17:59:09+0000

Answer:

(x + 11)(x - 11)

Explanation:

Since
x^(2) and 121 are both perfect squares (
$\sqrt{x^(2)$ =
and
√(121) =
), we can write the difference of two perfect squares a and b in the factored form:
(√(a) +√(b) ) (√(a) - √(b) ) . Therefore, the factored form of x^2 - 121 is (x +11)(x - 11).

Hope this helped! :)

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