Question

What is the factored form of this equation?
x^2-121

Answer 1

(x + 11)(x - 11)

Explanation:

Since
`x^(2)` and 121 are both perfect squares (
`\sqrt{x^(2)` =
`x` and
`√(121)` =
`11`), we can write the difference of two perfect squares a and b in the factored form:
`(√(a) +√(b) ) (√(a) - √(b) )`. Therefore, the factored form of x^2 - 121 is (x +11)(x - 11).

Hope this helped! :)

Answer 2

Answer:(x+11)(x-11)

Explanation: