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Find the solution of Z^5=32 whose argument is strictly between 0 and 90 degrees

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Answer:


\|r\| = 32,
\theta = 0\,rad

Explanation:

This complex expression is computed from the De Moivre expression:


z^(5) = 32\cdot (\cos 5x + i \cdot \sin 5x)

Given that resultant expression is entirely real, the expression is simplified into this form:


32 = 32\cdot \cos 5x


\cos 5x = 1

The angle is 0 radians.

User Pavan Ebbadi
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