Question

Find the solution of Z^5=32 whose argument is strictly between 0 and 90 degrees

Answer 1

`\|r\| = 32`,
`\theta = 0\,rad`

Explanation:

This complex expression is computed from the De Moivre expression:

`z^(5) = 32\cdot (\cos 5x + i \cdot \sin 5x)`

Given that resultant expression is entirely real, the expression is simplified into this form:

`32 = 32\cdot \cos 5x`

`\cos 5x = 1`

The angle is 0 radians.