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Chase buys a new Camaro for 55.500. It will lose 15% in value per year He would like to sell the car when it gets to 20,000. When should he sell the car

what is the best model for the situation
f(x)= 55,500*
(.15)^(x)
f(x)= 55,500*
(.85)^(x)
f(x)= 55,500*
(1.15)^(x)
f(x)= 55,500*
(1.85)^(x)

How many years should he keep it
8 years
7 years
6 years
5 years

User Wes
by
3.4k points

1 Answer

1 vote

Answer:

To determine when Chase should sell the car, we need to calculate how many years it will take for the car's value to reach $20,000.

Given that the car loses 15% of its value each year, we can use the formula:

f(x) = 55,500 * (1 - 0.15)^x

where x represents the number of years.

To find when the car's value reaches $20,000, we need to solve the equation:

20,000 = 55,500 * (1 - 0.15)^x

To simplify, let's rewrite the equation using 0.85 as the decimal representation of (1 - 0.15):

20,000 = 55,500 * 0.85^x

Now, we need to solve for x. To do this, we can take the logarithm of both sides of the equation:

(20,000) = (55,500 * 0.85^x)

Using logarithm properties, we can rewrite the equation as:

(20,000) = (55,500) + (0.85^x)

Applying the power rule of logarithms, which states that (a^b) = b * (a), we get:

(20,000) = (55,500) + x * (0.85)

Now, we can substitute the values of (20,000) and (55,500), which are approximately 4.301 and 4.743, respectively:

4.301 = 4.743 + x * (0.85)

Simplifying the equation:

-0.442 = x * (0.85)

Dividing both sides by (0.85):

x = -0.442 /(0.85)

Using a calculator, we find that x is approximately 5.264.

Therefore, Chase should sell the car after approximately 5 years to reach a value of $20,000.

In the given options, the correct answer is:

- Sell the car after 5 years.

User NSTJ
by
2.8k points