Question

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =4 to =1.

Answer 1

Step-by-step explanation:

Energy of a orbital in hydrogen atom

En =
`-(13.6 )/(n^2) eV`

for n = 4

E₄ =
`-(13.6 )/(4^2) eV`

E₁ =
`-(13.6 )/(1^2) eV`

the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n =4 to n =1.

E₄ - E₁ =
`( (13.6 )/(1^2) -(13.6 )/(4^2) )`

= 12.75 eV .