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If 3.63 mol of an ideal gas has a pressure of 5.36 atm and a volume of 97.77 L, what is the temperature of the sample?

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Answer:

1.76 × 10³ K

Step-by-step explanation:

Given data

  • Moles of the gas sample (n): 3.63 mol
  • Pressure of the gas (P): 5.36 atm
  • Volume of the container in which the gas is (V): 97.77 L
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

For an ideal gas, we can calculate the temperature of the sample using the ideal gas equation.


P * V = n * R * T\\T = (P * V)/(n * R) = (5.36atm * 97.77L)/(3.63mol * (0.0821atm.L)/(mol.K) ) = 1.76 * 10^(3) K

The sample is at 1.76 × 10³ K.

User Aaronius
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