Question

How many mL of 1.00M HCl are needed to neutralize 400mL of 0.200M NaOH?

Answer 1

80 mL

Step-by-step explanation:

M= mol solute/ L solution

mol solute= M * L solution

mol solute = (0.200 M * 0.4 L)

mol solute = 0.08 mol NaOH= mol OH

We need the same amount of H mol to neutralize

L solution= mol solute/M

L solution= 0.08 mol HCl/ 1.00M

L solution= 0.08 L= 80 mL