Question

A 25.0 mL sample of 0.123 M HCl was titrated with 18.04 mL of NaOH . What is the concentration of the NaOH ?

Answer 1

0.170 M

Step-by-step explanation:

M1V1=M2V2

(25.0mL)(0.123M)=(18.04mL)(x)

x= 0.170 M

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