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What is the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1)? x2 + (y + 4)² = StartRoot 5 EndRoot (x – 1)² + (y + 2)² = 5 (x + 4)² + y² = 5 (x + 2)² + (y – 1)² = StartRoot
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What is the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1)? x2 + (y + 4)² = StartRoot 5 EndRoot (x – 1)² + (y + 2)² = 5 (x + 4)² + y² = 5 (x + 2)² + (y – 1)² = StartRoot 5 EndRoot

User Jurakin
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2 Answers

3 votes

Answer:

C. (x + 4)² + y² = 5

Explanation:

What is the equation of a circle with a center at (–4, 0) that passes through the-example-1
User Sanket Singh
by
8.0k points
7 votes

Answer:

C. (x + 4)² + y² = 5

Explanation:

User Chris Woodruff
by
8.4k points
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