80.6k views
4 votes
A sequence is defined by the recursive function f(n + 1) = 1/3f(n). If f(3) = 9 , what is f(1)

User Yuu Woods
by
7.7k points

2 Answers

7 votes

Answer: D on edge 2020

Explanation:

:)

User Ray Garner
by
8.2k points
6 votes

Answer:

f(1) = 81

Explanation:

given is f(n + 1) = 1/3f(n)

f(3) = 9

ayou need to find f(0) before you can answer what is f(1).

Just start by applying for...

n=0

f(0+1) = 1/3 * f(0)

f(1) = 1/3 * f(0)

n=1

f(1+1) = 1/3 * 1/3*f(0)

f(2) = 1/9 * f(0)

n=2

f(2+1) = 1/3 * 1/9* f(0)

f(3) = 1/27 * f(0)

But it is given that f(3) = 9 so substitute this in the line above to calculate the value of f(0)....

9 = 1/27 * f(0)

Multiply left and right of the = sing by 27 gives

f(0) = 27 * 9

f(0) = 243

We already know this next line because we started with n=0

f(1) = 1/3 * f(0)

Substitute f(0) = 243 in the line above to finally calculate the value of f(1).

f(1) = 1/3 * 243

f(1) = 81

User TrueEddie
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories