Answer:
C). Because the sets are not symmetrical, the IQR should be used to compare the data sets.
D). Because the sets contain outliers, the median should be used to compare the data sets.
E). The mean and mode cannot be accurately determined based on the type of data display.
Step-by-step explanation:
The above statements regarding the data sets are correct. Since the given data sets are non-symmetrical and the involvement of outliers, median must not be employed for comparison(due to irregularity) and therefore, Interquartile Range must be employed to compare the data of height of students of the class. Mode or mean can't be ascertained precisely as the display of data is inconsistent and disproportionate. Therefore, options C, D, and E are the correct answers.