Question

What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2

Answer 1

101 i hope this helps

Explanation:

Given: A standard octagon has a span of 6 ft and a side length of 4.6 ft.

To discover the territory of a normal octagon(A) of side length an is given by :

`A=2*(1+√(2))a^(2)`

Given the length of side, a= 4.6 ft

Substitute the estimation of a=4.6 ft in the given equation of zone:

`A=2*(1+√(2) )*(4.5)^(2)`

or then again

`A=(2+2√(2) )*(21.16)`

or then again

`A=(2+2.828) *(21.16)`

Streamline:

`A=4.828*21.16=102.16048 ft^(2)`

along these lines, the inexact zone of ordinary octagon is, 101 square ft