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What is the approximate area of the octagon? 71 ft2 101 ft2 110 ft2 202 ft2

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Answer:

101 i hope this helps

Explanation:

Given: A standard octagon has a span of 6 ft and a side length of 4.6 ft.

To discover the territory of a normal octagon(A) of side length an is given by :


A=2*(1+√(2))a^(2)

Given the length of side, a= 4.6 ft

Substitute the estimation of a=4.6 ft in the given equation of zone:


A=2*(1+√(2) )*(4.5)^(2)

or then again


A=(2+2√(2) )*(21.16)

or then again


A=(2+2.828) *(21.16)

Streamline:


A=4.828*21.16=102.16048 ft^(2)

along these lines, the inexact zone of ordinary octagon is, 101 square ft

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